## What separates the boundary value problem from initial value problem?

A boundary value problem has conditions specified at the extremes (“boundaries”) of the independent variable in the equation whereas an initial value problem has all of the conditions specified at the same value of the independent variable (and that value is at the lower boundary of the domain, thus the term “initial” …

## How do you solve for variable separation?

The method of separation of variables involves finding solutions of PDEs which are of this product form. In the method we assume that a solution to a PDE has the form. u(x, t) = X(x)T(t) (or u(x, y) = X(x)Y (y)) where X(x) is a function of x only, T(t) is a function of t only and Y (y) is a function y only.

When can you use separation of variables PDE?

In order to use the method of separation of variables we must be working with a linear homogenous partial differential equations with linear homogeneous boundary conditions.

### What is the advantage of separation of variables method?

With the method of separation of variables, we can obtain formulas for solutions to a number of differential equations that were previously accessible only by Euler’s method. One of the advantages of a formula is that it allows us to see how the parameters in the problem affect the solution.

### Why can we do separation of variables?

Separation of variables is a method of solving ordinary and partial differential equations. ., and then plugging them back into the original equation. This technique works because if the product of functions of independent variables is a constant, each function must separately be a constant.

How do you divide two variables?

Step 1 Separate the variables by moving all the y terms to one side of the equation and all the x terms to the other side:

1. Multiply both sides by dx:dy = (1/y) dx. Multiply both sides by y: y dy = dx.
2. Put the integral sign in front:∫ y dy = ∫ dx. Integrate each side: (y2)/2 = x + C.
3. Multiply both sides by 2: y2 = 2(x + C)